# How do you find the value of the discriminant and determine the nature of the roots x^2 + 3x = 40 ?

HI,discriminant is
${b}^{2} - 4 a c$ for quadratic $a {x}^{2}$+bx+c=0

this can be
1.greater then zero
2.equal to zero
3.less than zero

It depends on the sign of ${x}^{2}$ term
if ${x}^{2}$ is positive ${b}^{2} - 4 a c$
thrn ${b}^{2} - 4 a c \ge 0$
hence
b=3 ,a=1
c=-40
then ....
9-4(1)(-40)= is the value of determinant