# How do you find the value of the discriminant and determine the nature of the roots -2x^2-8x-14=-6?

Aug 5, 2016

$y = - 2 {x}^{2} - 8 x - 8 = 0$
$D = {b}^{2} - 4 a c = 64 - 64 = 0$
Since D = 0, there is a double-root at $x = - \frac{b}{2 a} = \frac{8}{-} 4 = - 2$