Question

How do you find the value of the discriminant and determine the nature of the roots `-2x^2-8x-14=-6`?

Answer 1

Double -root at x = - 2

Explanation:

Bring the quadratic equation to standard form:
`y = -2x^2 - 8x - 8 = 0`
Use the nee Quadratic formula in graphic fomm (Socratic Search)
`D = b^2 - 4ac = 64 - 64 = 0`
Since D = 0, there is a double-root at `x = - b/(2a) = 8/-4 = - 2`
graph{-2x^2 - 8x - 8 [-10, 10, -5, 5]}