How do you find the value of the discriminant and state the type of solutions given #-2x^2-8x-14=-6#?

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Answer 1 · 2018-07-26T21:48:08

Determinant #=0# & the roots are real & equal

The given quadratic equation:

#-2x^2-8x-14=-6#

#x^2+4x+4=0#

Comparing the above equation with the standard form of quadratic equation: #ax^2+bx+c=0#, we get

#a=1, b=4, c=4#

hence the determinant is given as

#b^2-4ac=4^2-4(1)(4)=0#

Since #b^2-4ac=0# the roots are real & equal.