How do you find the value of x if #log_x 6 = 0.5#?

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Answer 1 · 2015-05-08T18:23:25

Use the definition of logarithm as #log_ba=x ->b^x=a#
So:
#6=x^0.5#
or
#6=sqrt(x)#
squaring both sides:
#x=6^2=36#