How do you find the values of the six trigonometric functions of #t= ((7 pi) / 6)#?

1 Answer
Jun 21, 2016

Find values of trig functions

Explanation:

Trig table and unit circle -->
#sin t = sin ((7pi)/6) = sin (pi/6 + pi) = - sin (pi/6) = -1/2#
#cos t = cos ((7pi)/6) = cos (pi/6 + pi) = - cos (pi/6) = -sqrt3/2#
#tan t = sin/(cos) = (-1/2)(- 2/sqrt3) = 1/sqrt3 = sqrt3/3#
#cot t = sqrt3/1 = sqrt3#
#sec t = 1/(cos) = -2/sqrt3 = -2sqrt3/3#
#csc t = 1/(sin) = -2#