# How do you find the values of x and y given [(-12), (2), (12y)]=[(6x), (y+1), (10-x)]?

$x = - 2$ and $y = 1$
After equating rows, $6 x = - 12$, $y + 1 = 2$ and $12 y = 10 - x$
After solving them, I found $x = - 2$ and $y = 1$