# How do you find the Vertical, Horizontal, and Oblique Asymptote given #f(x)=(6x^2+2x-1 )/ (x^2-1)#?

##### 1 Answer

Nov 16, 2016

The vertical asymptotes are

The horizontal asymptote is

No oblique asymptote

#### Explanation:

The denominator is

As we cannot divde by

Therefore the vertical asymptotes are

As the degree of the numerator

For the limit, we take the term with the highest coefficient

The horizontal asymptote is

graph{(y-(6x^2+2x-1)/(x^2-1))(y-6)=0 [-12.83, 12.49, -1.84, 10.83]}