How do you find the Vertical, Horizontal, and Oblique Asymptote given #y = (x^2 - 5x + 6)/( x - 3)#?

Question

767 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-07T10:54:17

This is the equation of the line #y=x-2#

Let's factorise the numerator

#x^2-5x+6=(x-3)(x-2)#

So,

#y=(x^2-5x+6)/(x-3)=(cancel(x-3)(x-2))/cancel(x-3)#

#y=x-2#

This is the equation of a line

graph{(x^2-5x+6)/(x-3) [-12.66, 12.65, -6.33, 6.33]}