# How do you find the vertical, horizontal and slant asymptotes of: #f(x)=1/(x^2-2x-8 )#?

##### 1 Answer

Jan 21, 2017

#### Answer:

The vertical asymptotes are

The horizontal asymptote is

No slant asymptote.

#### Explanation:

Let's factorise the denominator

So,

As you cannot divide by

The vertical asymptotes are

As the degree of the numerator is

The horizontal asymptote is

graph{(y-1/(x^2-2x-8))(y)(y-50x-100)(y-50x+200)=0 [-9.84, 10.18, -5.175, 4.825]}