# How do you find the vertical, horizontal and slant asymptotes of: #f(x) = (4x)/(x^2-25)#?

##### 1 Answer

#### Answer:

The VA's are

#### Explanation:

Factor the denominator.

The vertical asymptotes can be found by setting the denominator equal to zero and solving for x. f(x) is undefined when the denominator = 0.

The horizontal asymptote is found by comparing the degree of the numerator to the degree of the denominator.

*If the degree of the numerator is less than the degree of the numerator, the HA is y=0.
*If the degrees are equal, the HA is the leading coefficient of the numerator divided by the leading coefficient of the denominator.

*If the degree of the numerator is greater, there is a slant asymptote.

In

There are no slant asymptotes because the degree of the numerator is not greater than the degree of the denominator.