# How do you find the vertical, horizontal and slant asymptotes of: #(x^2-2x+1)/(x^3-x^2+x-1)#?

##### 1 Answer

Feb 15, 2017

#### Answer:

Horizontal asymptote :

Indeterminate hole : at x = 1.

#### Explanation:

Sans indeterminate hole at x = 1,

As

So, y = 0 is the asymptote.

graph{((x-1)/(x^2+1)-y)y((x-1)^2+y^2-.004)=0x^2 [-5, 5, -2.5, 2.5]}

Socratic graph with asymptote and location of indeterminate hole.

The hole is a 0-D point, and so, it is termed indeterminate, in

graphics.