How do you find the vertical, horizontal and slant asymptotes of: x/(x^2+x-6)?

Dec 22, 2016

Vertical asymptotes x=-3 and x=2

Horizontal asymptote at y=0

No slant asymptote

Explanation:

Rewrite f(x) after factorising the denominator as follows

$f \left(x\right) = \frac{x}{\left(x + 3\right) \left(x - 2\right)}$

f(x) has vertical asymptotes at x= -3 and x=2. It has an horizontal asymptotes at y=0 There are no slant asymptotes