# How do you find the vertical, horizontal and slant asymptotes of: #y = ( 2x-4)/(x^2+2x+1)#?

##### 1 Answer

#### Answer:

**Vertical asymptote is at** **horizontal asymptote is at x-axis** **and there is no slant asymptote.**

#### Explanation:

Vertical asymptote : We will have vertical asymptotes at those

values of

Horizontal asymptote: If m > n (that is, the degree of the

denominator is larger than the degree of the numerator), then the

graph of y = f(x) will have a horizontal asymptote at

(i.e., the x-axis). So horizontal asymptote is at x-axis

Slant asymptote: if the numerator's degree is greater (by a margin

of 1), then we have a slant asymptote which is found by doing long

division. So there is no slant asymptote.

graph{(2(x-2))/(x+1)^2 [-40, 40, -20, 20]} [Ans]