# How do you find the vertical, horizontal or slant asymptotes for #(2x^2+x-7)/(x^2-1)#?

##### 1 Answer

Nov 2, 2016

#### Answer:

The vertical asymptotes are

The horizontal asymptote is

#### Explanation:

The denominator

As we cannot divide by zero, the vertical asymptotes are

As the degree of the numerator and denominator are the same, we don't have slant asymptotes

limit

So

graph{(2x^2+x-7)/(x^2-1) [-10, 10, -5, 5]}