Question

How do you find the vertical, horizontal or slant asymptotes for `9/(1+2e^-x)`?

Answer 1

Horizontal asymptotes: `y=0 larr and y=9 rarr`. See the illustrative graph.

Explanation:

`x in (-oo, oo) and y in (0, 9)`

y-intercept ( x = 0 ) ; 3

y to 0`, as` x to -oo and y to 9`, as`x to oo#.

graph{y(1+2e^(-x))-9=0 [-35.48, 35.47, -17.66, 17.81]}