# How do you find the vertical, horizontal or slant asymptotes for #9/(1+2e^-x)#?

##### 1 Answer

Dec 7, 2016

#### Answer:

Horizontal asymptotes:

#### Explanation:

y-intercept ( x = 0 ) ; 3

y to 0

graph{y(1+2e^(-x))-9=0 [-35.48, 35.47, -17.66, 17.81]}