# How do you find the vertical, horizontal or slant asymptotes for f(x)= -1/(x+1)^2?

$x = - 1$ Vertical Asymptote
$y = 0$ Horizontal Asymptote
No Slant Asymptote

#### Explanation:

y approaches zero when x approaches infinity therefore $y = 0$ is a horizontal asymptote.

x approaches -1 when y approaches infinity therefore $x = - 1$ is a vertical asymptote

${\left(x + 1\right)}^{2} = - \frac{1}{y} \text{ " }$when y is so large, the right sides of the equation is almost zero and

$x + 1 = 0$

God bless...I hope the explanation is useful..