Question

How do you find the vertical, horizontal or slant asymptotes for `f(x)= -1/(x+1)^2`?

Answer 1

`x=-1` Vertical Asymptote
`y=0` Horizontal Asymptote
No Slant Asymptote

Explanation:

y approaches zero when x approaches infinity therefore `y=0` is a horizontal asymptote.

x approaches -1 when y approaches infinity therefore `x=-1` is a vertical asymptote

`(x+1)^2=-1/y" " "`when y is so large, the right sides of the equation is almost zero and

`x+1=0`

God bless...I hope the explanation is useful..