How do you find the vertical, horizontal or slant asymptotes for #f(x)= -1/(x+1)^2#?

1 Answer

Answer:

#x=-1# Vertical Asymptote
#y=0# Horizontal Asymptote
No Slant Asymptote

Explanation:

y approaches zero when x approaches infinity therefore #y=0# is a horizontal asymptote.

x approaches -1 when y approaches infinity therefore #x=-1# is a vertical asymptote

#(x+1)^2=-1/y" " "#when y is so large, the right sides of the equation is almost zero and

#x+1=0#

God bless...I hope the explanation is useful..