# How do you find the vertical, horizontal or slant asymptotes for f(x) = 3(1/x)?

Mar 5, 2016

Asymptotes: y = 0 and x = 0.

#### Explanation:

x y = ${c}^{2}$ represents a rectangular hyperbola .
The axis is y = x.
the asymptotes are the axes of coordinates.
The two branches are in the 1st and 3rd quadrants.
Here, c = $\sqrt{3}$
Vertices are $\left(\sqrt{3} , \sqrt{3}\right) \mathmr{and} \left(- \sqrt{3} , - \sqrt{3}\right)$
The eccentricity of a rectangular hyperbola is $\sqrt{2}$.
The foci are $\left(\sqrt{6} , \sqrt{6}\right) \mathmr{and} \left(- \sqrt{6} , - \sqrt{6}\right)$(