# How do you find the vertical, horizontal or slant asymptotes for #f(x) = (x^2 - 8)/(x+3)#?

##### 1 Answer

Oct 14, 2017

#### Answer:

**Vertical asymptote at** **no horizontal asymptote and
slant asymptote**

#### Explanation:

values of x for which the denominator is equal to zero.

asymptote at

To find the horizontal asymptote, here the degree of the numerator

is

degree occurs in the numerator, the graph will have no horizontal

asymptote.

```
If the numerator's degree is greater (by a margin of 1), then
```

we have a slant asymptote which can be found by doing long

division of

Slant asymptote is

graph{(x^2-8)/(x+3) [-10, 10, -5, 5]} [Ans]