# How do you find the vertical, horizontal or slant asymptotes for f(x)= (x+3)/( x^2+4x+3)?

Vertical Asymptote: $x = - 1$
Horizontal Asymptote: $y = 0$
From the given $y = \frac{x + 3}{{x}^{2} + 4 x + 3} = \frac{x + 3}{\left(x + 3\right) \left(x + 1\right)} = \frac{1}{x + 1}$