Question

How do you find the vertical, horizontal or slant asymptotes for `h(x)=5^(x-2)`?

Answer 1

Horizontal : `y = 0 larr`

Explanation:

graph{y(y-5^x/25)=0 [-1.95, 1.948, -0.975, 0.975]}

`h=5^(x-2)=5^x5^(-2)=1/25 5^x>=0`

y-intercept ( x = 0 ) : 1/25

As `x to oo, y to oo`.

As `x to -oo, y to 0`.

So, the x-axis y = 0 is the asymptote.