# How do you find the vertical, horizontal or slant asymptotes for #m(x) = (1-x^2)/(x^3)#?

##### 1 Answer

Dec 17, 2016

#### Answer:

Horizontal:

Vertical:

#### Explanation:

As

As

There is no quotient in the division #y=(1-x^2)/x^3. So, there is no

slant asymptote.

Interestingly, the horizontal asymptote

y = 0 cuts the graph at

graph{yx^3-1+x^2=0 [-10, 10, -5, 5]}