# How do you find the vertical, horizontal or slant asymptotes for #R(x) = (3x) / (x^2 - 9)#?

##### 1 Answer

Feb 26, 2016

#### Answer:

vertical asymptotes at x = ± 3

horizontal asymptote at y = 0

#### Explanation:

Vertical asymptotes occur when the denominator of a rational function tends to zero. To find the equation let the denominator equal zero.

solve :

# x^2 - 9 = 0 → (x-3)(x+3 ) = 0 → x = ± 3# Horizontal asymptotes occur as

#lim_(x→±∞) f(x) → 0# If the degree of the numerator is less than the degree of the denominator , as in this question, numerator degree 1 , denominator degree 2. Then the equation is always y = 0.

Here is the graph of the function to illustrate.

graph{3x/(x^2-9) [-10, 10, -5, 5]}