# How do you find the vertical, horizontal or slant asymptotes for #((x^2)+3)/((9x^2)-80x-9)#?

##### 1 Answer

Dec 31, 2016

#### Answer:

The vertical asymptotes are

No slant asymptote

The horizontal asymptote is

#### Explanation:

We can factorise the denominator

Let,

The domain of

As we cannot divide by

The vertical asymptotes are

As the degree of the numerator is

Now, we calculate the limits of

The horizontal asymptote is

graph{(y-(x^2+3)/(9x^2-80x-9))(y-1/9)=0 [-52.1, 51.93, -26, 25.94]}