# How do you find the vertical, horizontal or slant asymptotes for #(x )/(4x^2+7x-2) #?

##### 1 Answer

#### Answer:

The vertical asymptotes are

No slant asymptote

The horizontal asymptote is

#### Explanation:

Let's factorise the denominator

Let

The domain of

As we cannot divide by

So, the vertical asymptotes are

As the degree of the numerator is

To calculate the limits as x tends to

So, the horizontal asymptote is,

graph{x/(4x^2+7x-2) [-6.244, 6.243, -3.12, 3.123]}