# How do you find the vertical, horizontal or slant asymptotes for #y = e^x (1-x^2)#?

##### 1 Answer

#### Answer:

Horizontal asymptote at

#### Explanation:

Firstly, there are no singularities in this function (there is nowhere where we would have to "divide by 0"). As such there are no vertical asymptotic.

Lets look at the case where:

as the

This increases non-linearly and as such will not be asymptotic. So there are no asymptotes going when

Now let's look at when

again.

However in this case,

As such there will be a horizontal asymptote at

graph{e^x(1-x^2) [-10, 10, -5, 5]}