# How do you find the x and y intercept given 3x + 2y = 12?

Oct 27, 2015

The x-intercept is at$\left(4 , 0\right)$
The y-intercept is at$\left(0 , 6\right)$

#### Explanation:

$3 x + 2 y = 12 \implies$ equation of a straight line in the standard form.

To find the x-intercept set y to zero then solve for x:
$3 x + 2 \cdot 0 = 12$
$3 x = 12$
$x = 4$
$\therefore$ the x-intercept is at $\left(4 , 0\right)$

To find the y-intercept set x to zero then solve for y:
$3 \cdot 0 + 2 y = 12$
$2 y = 12$
$y = 6$
$\therefore$ the y-intercept is at $\left(0 , 6\right)$