How do you find the x and y intercept of -16x^2+24x-5?

Jul 17, 2015

Solve $y = - 16 {x}^{2} + 24 x - 5.$
To find x-intercepts, solve $y = - \left(16 {x}^{2} - 24 x + 5\right) = 0 \left(1\right)$
Transformed equation: $y ' = {x}^{2} - 24 x + 80. \left(2\right)$ Roots have same sign.
Back to original equation (1), the 2 real roots are: $x 1 = \frac{y 1}{a} = \frac{4}{16} = \frac{1}{4}$ and $x 2 = \frac{y 2}{a} = \frac{20}{16} = \frac{5}{4}$