How do you find the x and y intercept of #-3x+9y=-18#?

1 Answer
May 17, 2017

Answer:

The #x#-intercept is #(6, 0)#
The #y#-intercept is #(0, -2)#

Explanation:

The #x#-intercept occurs when #y# equals zero, and the #y#-intercept is when #x# equals zero.

Knowing that, let's solve for our #x#-intercept by setting #y=0#.

#-3xx x+9xx0=-18#

#-3xx x=-18#

divide by #-3#

#x=6#

The #x#-intercept is #(6, 0)#

Now let's solve for the #y#-intercept

#-3 xx 0+9 xx y=-18#

#9 xx y=-18#

divide by #9# on both sides

#x=-2#

The #y#-intercept is #(0, -2)#

Just to check our work, let's graph the equation and see if our #x# and #y# intercepts match:

graph{-18=-3x+9y}

They match! Good job!