# How do you find the x and y intercept of 4y=3x+12?

Dec 17, 2016

The x-intercept is: $x = - 4$ or (-4, 0).

The y-intercept is: $y = 3$ or (0, 3)

#### Explanation:

To find the x-intercept you set $y$ equal to $0$ and solve for $x$:

$4 \cdot 0 = 3 x + 12$

$0 = 3 x + 12$

$0 - 12 = 3 x + 12 - 12$

$- 12 = 3 x + 0$

$- 12 = 3 x$

$\frac{- 12}{3} = \frac{3 x}{3}$

$- 4 = x$ or $x = - 4$ or (-4, 0).

To find the x-intercept you set $x$ equal to $0$ and solve for $y$:

$4 y = 3 \cdot 0 + 12$

$4 y = 0 + 12$

$4 y = 12$

$\frac{4 y}{4} = \frac{12}{4}$

$y = 3$ or (0, 3)