How do you find the x and y intercept of #5x-y=35#?

1 Answer
Jan 18, 2017

Answer:

See the entire process below:

Explanation:

To find the x-intercept substitute #color(red)(0)# for #color(red)(y)# and solve for #x#:

#5x - color(red)(y) = 35# becomes:

#5x - color(red)(0) = 35#

#5x = 35#

#(5x)/color(red)(5) = 35/color(red)(5)#

#(color(red)(cancel(color(black)(5)))x)/cancel(color(red)(5)) = 7#

#x = 7#

To find the y-intercept substitute #color(red)(0)# for #color(red)(x)# and solve for #y#:

#5color(red)(x) - y = 35# becomes:

#(5 xx color(red)(0)) - y = 35#

#0 - y = 35#

#-y = 35#

#color(red)(-1) xx - y = color(red)(-1) xx 35#

#y = -35#

The x-intercept is #7# or (7, 0)

The y-intercept is #-35# or (0, -35)