# How do you find the x and y intercept of 6x + 4y = 12?

Feb 27, 2017

To find the x-intercept set $y$ equal to $0$ and solve for $x$:

$6 x + 4 y = 12$ becomes:

$6 x + \left(4 \cdot 0\right) = 12$

$6 x + 0 = 12$

$6 x = 12$

$\frac{6 x}{\textcolor{red}{6}} = \frac{12}{\textcolor{red}{6}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{6}}} x}{\cancel{\textcolor{red}{6}}} = 2$

$x = 2$ therefore the x-intercept is $2$ or $\left(2 , 0\right)$

To find the y-intercept set $x$ equal to $0$ and solve for $y$:

$6 x + 4 y = 12$ becomes:

$\left(6 \times 0\right) + 4 y = 12$

$0 + 4 y = 12$

$4 y = 12$

$\frac{4 y}{\textcolor{red}{4}} = \frac{12}{\textcolor{red}{4}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{4}}} y}{\cancel{\textcolor{red}{4}}} = 3$

$y = 3$ therefore the y-intercept is $3$ or $\left(0 , 3\right)$