How do you find the x and y intercept of #6x + 8y = - 2#?

1 Answer
Jul 28, 2016

Answer:

#x#-intecept is #x=-1/3#
#y#-intecept is #y=-1/4#

Explanation:

#6x+8y=-2#
#x#-intecept is when #y=0#
So putting #y=0# in the above equation we get
#6x+8(0)=-2#
or
#6x+0=-2#
or
#6x=-2#
or
#x=-2/6#
or
#x=-1/3#

#y#-intecept is when #x=0#
So putting #x=0# in the above equation #6x+8y=-2#
we get
#6(0)+8y=-2#
or
#0+8y=-2#
or
#8y=-2#
or
#y=-2/8#
or
#y=-1/4#