# How do you find the x and y intercept of 6x + 8y = - 2?

Jul 28, 2016

$x$-intecept is $x = - \frac{1}{3}$
$y$-intecept is $y = - \frac{1}{4}$

#### Explanation:

$6 x + 8 y = - 2$
$x$-intecept is when $y = 0$
So putting $y = 0$ in the above equation we get
$6 x + 8 \left(0\right) = - 2$
or
$6 x + 0 = - 2$
or
$6 x = - 2$
or
$x = - \frac{2}{6}$
or
$x = - \frac{1}{3}$

$y$-intecept is when $x = 0$
So putting $x = 0$ in the above equation $6 x + 8 y = - 2$
we get
$6 \left(0\right) + 8 y = - 2$
or
$0 + 8 y = - 2$
or
$8 y = - 2$
or
$y = - \frac{2}{8}$
or
$y = - \frac{1}{4}$