# How do you find the x and y intercept of 7x + 5y = 42?

$x$ intercept is $\left(6 , 0\right)$ , $y$ intercept is $\left(0 , 8 \frac{2}{5}\right)$
Putting $x = 0$, we can get y intercept as $5 y = 42 \mathmr{and} y = \frac{42}{5}$
So y intercept is $\left(0 , \frac{42}{5}\right) \mathmr{and} \left(0 , 8 \frac{2}{5}\right)$
Putting $y = 0$, we can get y intercept as $7 x = 42 \mathmr{and} x = 6$
So x intercept is $\left(6 , 0\right)$ graph{-7/5x +42/5 [-40, 40, -20, 20]}[Ans]