How do you find the x and y intercept of #y=-4.7x+1.2#?

1 Answer
Mar 29, 2017

Answer:

See the entire solution process below:

Explanation:

y-INTERCEPT) To find the y-intercept, set #x# equal to #0# and calculate #y#;

#y = -4.7x + 1.2# becomes:

#y = (-4.7 xx 0) + 1.2#

#y = 0 + 1.2#

#y = 1.2#

The y-intercept is #1.2# or #(0, 1.2)#

x-INTERCEPT) To find the x-intercept, set #y# equal to #0# and solve for #x#;

#y = -4.7x + 1.2# becomes:

#0 = -4.7x + 1.2#

#0 - color(red)(1.2) = -4.7x + 1.2 - color(red)(1.2)#

#-1.2 = -4.7x + 0#

#-1.2 = -4.7x#

#(-1.2)/color(red)(-4.7) = (-4.7x)//color(red)(-4.7)#

#(-1.2)/color(red)(-4.7) = (-4.7x)/color(red)(-4.7)#

#0.255 = (color(red)(cancel(color(black)(-4.7)))x)/cancel(color(red)(-4.7))#

#0.255 = x#

#x = 0.255# rounded to the nearest thousandth

The x-intercept is #0.255# or #(0.255, 0)#