# How do you find the x and y intercept of y=x^2-2x-3?

$y = {x}^{2} - 2 x - 3.$
To find the 2 x-intercepts, make y = 0 and solve the quadratic equation: $y = {x}^{2} - 2 x - 3 = 0$.
Since (a - b + c = 0), use the shortcut. Two real roots are $x = - 1$ and $x = - \frac{c}{a} = 3$