Question

How do you find the x and y intercepts for `15x-9y=27`?

Answer 1

The `y`-intercept is when `x=0` and the `x`-intercept is when `y=0`

Explanation:

To cut a corner you may have noticed that all numbers are divisable by `3`. So you get:

`5x-3y=9`

Set `x=0`
`5*0-3y=9->y=-3->(0,-3)`

Set `y=0`
`5x-3*0=9->x=9/5-> (+9/5,0)`
graph{5x/3-3 [-10, 10, -5, 5]}