# How do you find the x and y intercepts for 15x-9y=27?

Mar 11, 2016

The $y$-intercept is when $x = 0$ and the $x$-intercept is when $y = 0$

#### Explanation:

To cut a corner you may have noticed that all numbers are divisable by $3$. So you get:

$5 x - 3 y = 9$

Set $x = 0$
$5 \cdot 0 - 3 y = 9 \to y = - 3 \to \left(0 , - 3\right)$

Set $y = 0$
$5 x - 3 \cdot 0 = 9 \to x = \frac{9}{5} \to \left(+ \frac{9}{5} , 0\right)$
graph{5x/3-3 [-10, 10, -5, 5]}