How do you find the x and y intercepts for #2x + 4y = -8#?

2 Answers
May 24, 2018

Answer:

See explanation.

Explanation:

To find #x# interxept of a function you have to substitute #0# for #y# and solve the equation for #x#:

#2*x+4*0=-8#

#2x=-8#

#x=-4#

The #x# intercept is the point #(-4,0)#.

To find #y# intercept you have to substitute #0# for #x# and solve the equation for #y#:

#2*0+4*y=-8#

#4y=-8#

#y=-2#

The #y# intercept is the point #(0,-2)#.

May 24, 2018

Answer:

x-intercept = #(-4,0)#
y-intercept = #(0,-2#)

Explanation:

x-intercept is when #y=0#
y-intercept is when #x=0#

Step 1:
Lets find the x-intercept by putting #y=0#

#2x+4y=-8#

#2x +(4 xx 0) = -8#

#2x +0 = -8#

#2x=-8#

#x= -8/2#

#x = -4# ------> x-intercept is #(-4,0)#

Step 2:
Lets find the y-intercept by putting #x=0#

#2x+4y=-8#

#(2 xx 0) +4y = -8

#0 + 4y = -8#

#4y=-8#

#y=-8/4#

#y = -2# -----> y-intercept is #(0,-2)#

if we plot the graph, we get the same. enter image source here