# How do you find the x and y intercepts for 2x - y = 0?

Jan 20, 2016

x intercept is at x=0 and y intercept is at y-0

#### Explanation:

This is a straight line graph that look like this:

You find the y intercept by making x=0 in the equation. That is because the graph crosses the y-axis at x=0

You find the x intercept by making y=0 in the equation. That is because the graph crosses the x-axis at y=0

Given:$\text{ } \textcolor{b r o w n}{2 x - y = 0}$

$\textcolor{red}{\text{~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~}}$
$\textcolor{g r e e n}{\text{Changing the equation format into:"" " y="something}}$

Add$\textcolor{b l u e}{\text{ "y" }}$ to both sides giving

$\textcolor{b r o w n}{2 x - y \textcolor{b l u e}{+ y} = 0 \textcolor{b l u e}{+ y}}$

$\textcolor{g r e e n}{2 x = y}$

$\textcolor{red}{\text{~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~}}$

$\textcolor{b l u e}{\text{To find the x intercept (crosses the x-axis)}}$

Set $y = 0$

so $y = 2 x$ becomes

$0 = 2 x$

Divide both sides by 2 giving

$\frac{0}{2} = \frac{2}{2} \times x$

But $\frac{0}{2} = 0 \text{ and } \frac{2}{2} = 1$

$0 = 1 \times x$

$0 = x$

$\textcolor{b l u e}{\text{So the x intercept is at } x = 0}$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$\textcolor{g r e e n}{\text{To find the y intercept (crosses the y-axis)}}$

Set $x = 0$ giving

so $y = 2 x$ becomes

$y = 2 \times 0$

But $2 \times 0 = 0$

So $y = 0$

$\textcolor{g r e e n}{\text{So the y intercept is at } y = 0}$