How do you find the x and y intercepts for #2x - y = 0#?

1 Answer
Jan 20, 2016

Answer:

x intercept is at x=0 and y intercept is at y-0

Explanation:

This is a straight line graph that look like this:
enter image source here

You find the y intercept by making x=0 in the equation. That is because the graph crosses the y-axis at x=0

You find the x intercept by making y=0 in the equation. That is because the graph crosses the x-axis at y=0

Given:#" "color(brown)( 2x-y=0)#

#color(red)("~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~")#
#color(green)("Changing the equation format into:"" " y="something")#

Add#color(blue)(" "y" ")# to both sides giving

#color(brown)(2x-ycolor(blue)(+y)=0color(blue)(+y))#

#color(green)(2x=y)#

#color(red)("~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~")#

#color(blue)("To find the x intercept (crosses the x-axis)")#

Set #y=0#

so #y=2x# becomes

#0=2x#

Divide both sides by 2 giving

#0/2= 2/2xx x#

But #0/2=0" and "2/2=1 #

#0=1 xx x#

#0=x#

#color(blue)("So the x intercept is at "x=0)#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(green)("To find the y intercept (crosses the y-axis)")#

Set #x=0# giving

so #y=2x# becomes

#y=2xx 0#

But #2xx0=0#

So #y=0#

#color(green)("So the y intercept is at "y=0)#