How do you find the x and y intercepts for #4x-2y=8#?

2 Answers
Nov 16, 2015

Answer:

Rearrange into the form #y=mx+c# and substitue it #x# and #y# values of 0.

Explanation:

Rearrange into the form #y=mx+c#

To rearrange into the form #y=mx+c# we need to get #y# on its own. To do this we can take #4x# away from both sides to get:

#-2y = 8-4x#

Next we'll multiply both sides by -1 to flip the signs:

#2y = 4x-8#

Finally we'll divide by 2:

#y = 2x-4#

Finding the #x# intercept
On the #x# axis we know that the #y# value is alwways 0 so we can substitute this into the equation and rearrange to find an #x# value.

#0=4x-8#

Add 8 to both sides:

#8=4x#

Divide by 4:

#x=2#

So we know the #x# intercept is at the point #(2,0)#

Finding the #y# intercept

At the #y# intercept we know that the #x# value is always 0.

Finding the #y# value is easy. The #c# value in #y=mx+c# gives the #y# coordinate for the #y# intercept and we've already rearrange into that form we now know that the #y# value is -4!

So the #y# intercept is at the point #(0,-4)#

Nov 16, 2015

Answer:

x-intercept: #2#
y-intercept: #-4#

Explanation:

Given: #4x-2y=8#

x-intercept
The x-intercept is the value of #x# when #y=0#
#color(white)("XXX")4x-2(0)=8 rArr x=2#

y-intercept
The y-intercept is the value of #y# when #x=0#
#color(white)("XXX")4(0)-2y=8 rArr y=-4#