# How do you find the x and y intercepts for 4x-2y=8?

Nov 16, 2015

Rearrange into the form $y = m x + c$ and substitue it $x$ and $y$ values of 0.

#### Explanation:

Rearrange into the form $y = m x + c$

To rearrange into the form $y = m x + c$ we need to get $y$ on its own. To do this we can take $4 x$ away from both sides to get:

$- 2 y = 8 - 4 x$

Next we'll multiply both sides by -1 to flip the signs:

$2 y = 4 x - 8$

Finally we'll divide by 2:

$y = 2 x - 4$

Finding the $x$ intercept
On the $x$ axis we know that the $y$ value is alwways 0 so we can substitute this into the equation and rearrange to find an $x$ value.

$0 = 4 x - 8$

$8 = 4 x$

Divide by 4:

$x = 2$

So we know the $x$ intercept is at the point $\left(2 , 0\right)$

Finding the $y$ intercept

At the $y$ intercept we know that the $x$ value is always 0.

Finding the $y$ value is easy. The $c$ value in $y = m x + c$ gives the $y$ coordinate for the $y$ intercept and we've already rearrange into that form we now know that the $y$ value is -4!

So the $y$ intercept is at the point $\left(0 , - 4\right)$

Nov 16, 2015

x-intercept: $2$
y-intercept: $- 4$

#### Explanation:

Given: $4 x - 2 y = 8$

x-intercept
The x-intercept is the value of $x$ when $y = 0$
$\textcolor{w h i t e}{\text{XXX}} 4 x - 2 \left(0\right) = 8 \Rightarrow x = 2$

y-intercept
The y-intercept is the value of $y$ when $x = 0$
$\textcolor{w h i t e}{\text{XXX}} 4 \left(0\right) - 2 y = 8 \Rightarrow y = - 4$