# How do you find the x and y intercepts for 4x +3y-7=0?

Dec 18, 2015

$x$ intercept is $\frac{7}{4}$ and $y$ intercept is $\frac{7}{3}$.

#### Explanation:

For $y = 0$,
$\textcolor{w h i t e}{\times} 4 x - 7 = 0$
$\implies 4 x - 7 \textcolor{red}{+ 7} = 0 \textcolor{red}{+ 7}$
$\implies \textcolor{red}{\frac{1}{4} \times} 4 x = \textcolor{red}{\frac{1}{4} \times} 7$
$\implies x = \frac{7}{4}$

Therefore $x$ intercept is $\frac{7}{4}$.

For $x = 0$,
$\textcolor{w h i t e}{\times} 3 y - 7 = 0$
$\implies 3 y - 7 \textcolor{red}{+ 7} = 0 \textcolor{red}{+ 7}$
$\implies \textcolor{red}{\frac{1}{3} \times} 3 y = \textcolor{red}{\frac{1}{3} \times} 7$
$\implies x = \frac{7}{3}$

Therefore $y$ intercept is $\frac{7}{3}$.
graph{(-4x+7)/3 [-10, 10, -5, 5]}