How do you find the x and y intercepts for #4x=-6y-12#?
x-intercept = - 3
y-intercept = - 2
This is the equation of a straight line. When the line crosses the x-axis , the y-coord will be zero. By letting y = 0 and substituting into the equation will give the x-intercept.
y = 0 : 4x = - 12 → x = - 3
Similarly , when line crosses y-axis , x-coord will be zero.
x= 0 : - 6y - 12 = 0 → - 6y = 12 → y = - 2