# How do you find the x and y intercepts for #-4x-7y+7=0#?

##### 2 Answers

#### Answer:

I tried this:

#### Explanation:

You need to set

Let us find the

So, we get:

into your expression:

So the

Now for the

into your expression:

So the

Let us check and "see" our intercepts graphically:

graph{-(4/7)x+1 [-10, 10, -5, 5]}

#### Answer:

#### Explanation:

#"to find the intercepts that is where the graph crosses"#

#"the x an d y axes"#

#• " let x = 0, in the equation for y-intercept"#

#• " let y = 0, in the equation for x-intercept"#

#-4x-7y+7=0#

#rArr-4x-7y=-7#

#x=0rArr0-7y=-7rArry=1larrcolor(red)"y-intercept"#

#y=0rArr-4x+0=-7rArrx=7/4larrcolor(red)"x-intercept"#

graph{(y+4/7x-1)((x-7/4)^2+(y-0)^2-0.04)((x-0)^2+(y-1)^2-0.04)=0 [-10, 10, -5, 5]}