# How do you find the x and y intercepts for 5x-y+2=0?

Nov 30, 2015

$\left(0 , 2\right)$ and $\left(- \frac{2}{5} , 0\right)$

#### Explanation:

$5 x - y + 2 = 0$
for $x = 0$,
$- y + 2 = 0$
$\implies y = 2$
One of the intercepts is $\left(0 , 2\right)$
for $y = 0$,
$5 x + 2 = 0$
$\implies x = - \frac{2}{5}$
The other intercept is $\left(- \frac{2}{5} , 0\right)$