# How do you find the x and y intercepts for 8x + 3y = 48?

Dec 10, 2015

$x$ intercept: $\left(6 , 0\right)$
$y$ intercept: $\left(0 , 16\right)$

#### Explanation:

The $x$ intercept is a point on the $x$ axis, so it's a point with coordinates $\left(x , 0\right)$. Similarly, a point on the $y$ axis is a point of the form $\left(0 , y\right)$.

So, you find the intercept with one axis by setting the other variable to $0$:

$y$-intercept: set the $x$ coordinate to zero.

$8 \cdot 0 + 3 y = 48$

$3 y = 48$

$y = 16$

So, the point $\left(0 , 16\right)$ belongs to the line, and it is its $y$ incercept.

$x$-intercept: set the $y$ coordinate to zero.

$8 x + 3 \cdot 0 = 48$

$8 x = 48$

$x = 6$

So, the point $\left(6 , 0\right)$ belongs to the line, and it is its $x$ incercept.