How do you find the x and y intercepts for #8x + 3y = 48#?

1 Answer
Dec 10, 2015

Answer:

#x# intercept: #(6,0)#
#y# intercept: #(0,16)#

Explanation:

The #x# intercept is a point on the #x# axis, so it's a point with coordinates #(x,0)#. Similarly, a point on the #y# axis is a point of the form #(0,y)#.

So, you find the intercept with one axis by setting the other variable to #0#:

#y#-intercept: set the #x# coordinate to zero.

#8*0+3y=48#

#3y=48#

#y=16#

So, the point #(0,16)# belongs to the line, and it is its #y# incercept.

#x#-intercept: set the #y# coordinate to zero.

#8x+3*0=48#

#8x=48#

#x=6#

So, the point #(6,0)# belongs to the line, and it is its #x# incercept.