How do you find the x and y intercepts for #f(x) = (x-3)^2 + 17#?
1 Answer
Aug 2, 2017
Explanation:
#"to find the intercepts"#
#• " let x = 0, in the equation for y-intercept"#
#• " let y = 0, in the equation for x-intercepts"#
#x=0toy=(-3)^2+17=26larrcolor(red)" y-intercept"#
#y=0to(x-3)^2+17=0#
#rArr(x-3)^2=-17#
#AAx inRRcolor(white)(x) (x-3)^2>=0#
#rArr" there are no x-intercepts"#
graph{(x-3)^2+17 [-80, 80, -40, 40]}
