How do you find the x and y intercepts for #f(x) = (x-3)^2 + 17#?

1 Answer
Aug 2, 2017

Answer:

#"y-intercept "=26" no x-intercepts"#

Explanation:

#"to find the intercepts"#

#• " let x = 0, in the equation for y-intercept"#

#• " let y = 0, in the equation for x-intercepts"#

#x=0toy=(-3)^2+17=26larrcolor(red)" y-intercept"#

#y=0to(x-3)^2+17=0#

#rArr(x-3)^2=-17#

#AAx inRRcolor(white)(x) (x-3)^2>=0#

#rArr" there are no x-intercepts"#
graph{(x-3)^2+17 [-80, 80, -40, 40]}