How do you find the x and y intercepts for #x + 2y=3#?

1 Answer
Dec 19, 2015

Answer:

#x# intercept is #3# and #y# intercept is #3/2#

Explanation:

#x+2y=3#

For #y=0#,
#color(white)(xx)x=3#

For #x=0#,
#color(white)(xx)2y=3#
#=>color(red)(1/2xx)2y=color(red)(1/2xx)3#
#=>y=3/2#

Therefore, #x# intercept is #3# and #y# intercept is #3/2#:
graph{(3-x)/2 [-10, 10, -5, 5]}