# How do you find the x and y intercepts for x + 2y = 4?

The x intercept occurs when $y = 0$ and the y intercept occurs when $x = 0$
Therefore the x-intercept can be found from $x + 2 \cdot 0 = 4$
$x = 4$
The y-intercept is found from $0 + 2 y = 4$
$y = 2$