How do you find the x and y intercepts for #x - 2y = 8#?

1 Answer
Dec 4, 2015

Answer:

To find the x-intercept set #y=0# in the equation and solve for #x#.

To find the y-intercept set #x=0# in the equation and solve for #y#

Explanation:

Using the given equation #x-2y=8# as an example:

Setting #color(red)(y=0)#
#color(white)("XXX")x-2xxcolor(red)(0) = 8#
#color(white)("XXX")x=8#
The x-intercept is #8#

Setting #color(blue)(x=0)#
#color(white)("XXX")color(blue)(0)-2y=8#
#color(white)("XXX")-2y=8#
#color(white)("XXX")y=-4#
The y-intercept is #(-4)#