How do you find the x and y intercepts for #x +5y=0#?

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Answer 1 · 2016-01-07T09:55:33

(0;0)

We have to write the equation in the form:
#y=f(x)#

#5y=-x#

#y=-x/5#

The #x# intercept it's the point where:

#y=0#

then

#-x/5=0#

#x=0#

The #y# intercept is the point where:

#x=0#

then:
#y=-0/5=0#

in this case we have a line through the axis origin