How do you find the x and y intercepts for #y= -1/2x - 4#?

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Answer 1 · 2015-11-13T05:48:23

y-intercept #=-4#
x-intercept #=-8#

Given -

#y= -1/2x-4#

To find #y# intercept put #x=0# in the equation

At #x= 0; y = -1/2(0)-4= -4#

Alternate way -

The given equation in the slope-intercept form of #y=mx+c# Where #c# is y-intercept.

You can straight away state #-4# is y-intercept

To find the #x# intercept put #y=0#

#-1/2x-4=y#

#-1/2x-4=0#

#-1/2x=0 +4#
#-1/2x=4#

#x=4(-2/1)=-8#

#x=-8#